Practice free Mechanical Properties of Fluids (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Radius of a soap bubble is 'r', surface tension of soap solution is T. Then without incresing the temperature how much energy will be needed to double its radius.
$ w = 8 \pi T ( R_2^2 - R_1 ^2 ) = 8 \pi T ( (2r)^2 - (r)^2 ) = 24 \pi r^2 T $
A soap bubble of radius r is blown up to forma bubble of radius 2r under isothermal conditions if the T is the surface tension of soap solution the energy spent in the slowing is.
$ Energy spent = T \times increase in surface ared$ $ = T \times 2 ( 4 \pi ( 2r)^2 - 4 \pi r^2 ) = ( 24 \pi T r^2) joule $
The surface tension of a liquid is 5 N/m. If a thin film of the area 0.02 m2 is formed on a loop, then its surface energy will be
$ w = T \times \triangle A $
A frame made of a metalic wire enclosing O surface area Ais covered with a soap film. If the area of the frame metalic wire is reduced by 50% the energy of the soap film will be changed by
$ Surface energy = Surface tension \times surface ared $ $ E = T \times 2 A $ $ New surface energy F_1 = T \times 2 \left( { A \over 2} \right) $ $ \% decrase in surface energy = { E - E_i \over E } \times 100 $
Two small drops mercury, each of radius R, coaless the form a single large drop. The ratio of the total surface energies before and after the change is.
The ration of the total surface energies before and after the change $ = n^{1 \over 2 } : 1 = 2 ^ {1 \over 3} : 1 $
The work done is blowing a soap bubble of 10 cm radius is (surface tension od the soap solution is 3/100 N/m )
$ w = 8 \pi R^2 T $
A big drop of radius R is formed by 1000 small droplets of coater then the radius of small drop is
$ { 4 \over 3} \pi R^ 3 $
8000 identioal water drops are combined to form a bigdrop. Then the ration of the final surface energy to the intilial surface energy of all the drops together is
$ As volume remains constant R^3 = 8000 r^ 3 R = 20 r $ $ {Surface energy of one big drop \over Surface energy of 8000 small drop } = - { 4 \pi R ^2 T \over 8000 4 \pi r^2 -1 } $
The relation between surface tension T. Surface area A and surface energy E is given by.
$ Tension = { surface energy \over Area } = or T ={ E \over A } $
A liquid wets a solid completely. The menisions of the liquid in a sufficiently long tube is
A liquid that wets a solid completely will have a concave meniscus in a sufficiently long tube. This is because the adhesive forces between the liquid and the solid are stronger than the cohesive forces within the liquid, causing the liquid to climb up the walls of the tube, forming a concave shape.
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