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Mechanical Properties of Solids MCQs for NEET — Physics Questions with Answers

Practice free Mechanical Properties of Solids (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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The quality of the material which opposes the change in shape, volume or length is called

Intermolecular repulsion

Intermolecular behaviour

Viscosity

Elasticity

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Explanation

(d)

Elasticity of a material resists change in shape, size, and volume of material.

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A wire of length L and radius r is rigidly fixed at one end. On stretching the other end of the wire with a force F, the increase in its length is l. If another wire of same material but of length 2L and radius 2r is stretched with a force of 2F, the increase in its length will be

$\frac{l}{2}$

$\frac{l}{4}$

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Explanation

(a)

$l = \frac{F L}{A Y} = \frac{F L}{{πr}^{2} Y} ∴ l \propto \frac{F L}{r^{2}} (Y = c o n s \tan t) ∴ \frac{l_{2}}{l_{1}} = \frac{F_{2}}{F_{1}} \times \frac{L_{2}}{L_{1}} {(\frac{r_{1}}{r_{2}})}^{2} = 2 \times 2 \times {(\frac{1}{2})}^{2} = 1$

$∴ l_{2} = l_{1}$ i.e. increment in its length will be l.

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In steel, the Young's modulus and the strain at the breaking point are $2 \times 10^{11} N m^{- 2}$ and 0.15 respectively. The stress at the breaking point for steel is therefore -

$1.33 \times 10^{11} N m^{- 2}$

$1.33 \times 10^{12} N m^{- 2}$

$7.5 \times 10^{- 13} N m^{- 2}$

$3 \times 10^{10} N m^{- 2}$

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Explanation

(d) Breaking stress = strain $\times$ Young's modulus

$= 0.15 \times 2 \times 10^{11} = 3 \times 10^{10} N m^{- 2}$

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Which one of the following substances possesses the highest elasticity

Rubber

Glass

Steel

Copper

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Explanation

(c)

Modulus of elasticity gives the idea of elasticity, and steel has highest modulus of elasticity.

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Which one of the following quantities does not have the unit of force per unit area

Stress

Strain

Young's modulus of elasticity

Pressure

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Explanation

(b) Because strain is a dimensionless and unitless quantity.

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A copper wire and a steel wire of the same diameter and length are connected end to end and a force is applied, which stretches their combined length by 1 cm. The two wires will have

Different stresses and strains

The same stress and strain

The same strain but different stresses

The same stress but different strains

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Explanation

(d) $S t r e s s = \frac{F o r c e}{a r e a}$

In the present case, force applied and area of cross-section of wires are same, therefore stress has to be the same.

$S t r a i n = \frac{S t r e s s}{Y}$

Since the Young’s modulus of steel wire is greater than the copper wire, therefore, strain in case of steel wire is less than that in case of copper wire.

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The possible value of Poisson's ratio is

0.9

0.8

0.4

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Explanation

(d) Poisson’s ratio varies between – 1 and 0.5.

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Which of the following affects the elasticity of a substance

Hammering and annealing

Change in temperature

Impurity in substance

All of these

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Explanation

(d) The elasticity of substance is affected by impurity of substance hammering and anneasing change in the temperature.

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A wire of diameter 1mm breaks under a tension of 1000 N. Another wire, of same material as that of the first one, but of diameter 2 mm breaks under a tension of

500 N

1000 N

10000 N

4000 N

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Explanation

(d) Breaking force $\propto$ r²

If diameter becomes double then breaking force will become four times i.e. 1000 × 4 = 4000 N

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The force required to stretch a steel wire of cross-section $1 {cm}^{2}$ to 1.1 times its length would be $(Y = 2 \times 10^{11} N m^{- 2})$

$2 \times 10^{6} N$

$2 \times 10^{3} N$

$2 \times 10^{- 6} N$

$2 \times 10^{- 7} N$

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Explanation

(a) $F = A \times Y \times s t r a i n = 1 \times 10^{- 4} \times 2 \times 10^{11} \times 0.1 = 2 \times 10^{6} N$

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