Blog Log in Get Started Free

Motion in a Lane MCQs for NEET — Physics Questions with Answers

Q: Are these Motion in a Lane questions free to attempt?

Yes. You can attempt every Motion in a Lane question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

Q: Do I need an account to practise Motion in a Lane MCQs?

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

Q: Are these previous year NEET questions?

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.

Practice free Motion in a Lane (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

Language English हिंदी

Chapter Difficulty Show only questions I answered incorrectly Clear Register free for difficulty & keyword filters

● ● ● ● ●

A particle is moving in a circle of radius R with constant speed. The time period of the particle is T Now after time t = T/6 Range of a projectile is R and maximum height is H. Find the area covered by the path of the projectile and horizontal line.

A. $ { 2 \over 3 } RH$ B. $ { 5 \over 3 } RH$ C. $ { 3 \over 5 } RH$ D. $ { 6 \over 5 } RH$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$ A = \int _0^R y dx $ $ take \, y = x tan \theta - { gx^2 \over 2V_0 x cos \theta } $

● ● ● ● ●

Which of the following statements is false for a particle moving in a circle with a constant angular speed?

The accelaration vector points to the centre of the cycle.

The accelaration vector is tangent to the circle.

The velocity vector is tangent to the circle.

The velocity and accelaration vectors are perpendicular to each other.

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

When a particle moving in a circle with a constant angular speed.
Its velocity vector is tangent to the circle and the acceleration vector is along the radius of the circle. The velocity and acceleration vectors are perpendicular to each other.

● ● ● ● ●

Component of $3 \hat{i} + 4 \hat{j}$ perpendicular to $\hat{i} + \hat{j}$ and in the same plane as that of $3 \hat{i} + 4 \hat{j}$ is:

$\frac{1}{2} (\hat{j} - \hat{i})$

$\frac{3}{2} (\hat{j} - \hat{i})$

$\frac{5}{2} (\hat{j} - \hat{i})$

$\frac{7}{2} (\hat{j} - \hat{i})$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

● ● ● ● ●

Given that $\overset{⇀}{C} = \overset{⇀}{A} + \overset{⇀}{B} and \overset{⇀}{C}$ makes an angle $α with \overset{⇀}{A} and β with \overset{⇀}{B}$ . Which of the following options is correct?

$α cannot be less then β$

$α < β, if A < B$

$α < β, if A > B$

$α < β, if A = B$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

● ● ● ● ●

If the magnitude of sum of two vectors is equal to the magnitude of difference of the two vectors, the angle between these vectors is

90°

45°

180°

0°

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

(a)

$Suppose two vectors are P and Q . It is given that - |P + Q| = |P - Q| Let the angle between P and Q is θ . \Rightarrow P^{2} + Q^{2} + 2 PQcosθ = P^{2} + Q^{2} - 2 PQcosθ \Rightarrow cosθ = 0 = \cos 90^{0} \Rightarrow θ = 90^{0}$

● ● ● ● ●

A force of 6 N and another of 8 N can be applied together to produce the effect of a single force of -

1 N

11 N

15 N

20 N

You've reached today's free limit of 20 questions. Log in to keep practising for free.

● ● ● ● ●

Which of the sets given below may represent the magnitude of resultant of three vectors adding to zero?

2, 4, 8

4, 8, 16

1, 2, 1

0.5, 1, 2

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

(C)

$Let there be 3 vectors \vec{A}, \vec{B} & \vec{C} . Suppose magnitude of C is highest . For zero resultant, C \leq A + B Where A, B & C represents magnitude of \vec{A}, \vec{B} & \vec{C} For pair 1, 2, 1 C = 2 A = 1 B = 1 Also, 2 \leq 1 + 1$

● ● ● ● ●

A blind person after walking 10 steps in one direction, each of length 80 cm, turns randomly to the left or to the right by $90 ° .$ After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be -

$320 m$

$32 m$

$16 / \sqrt{2} m$

$16 \sqrt{2} m$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Each step is 80 cm, and the person takes 40 steps. If the person walks in a straight line after the initial turn, the maximum displacement is 40 Ã— 0.8 m = 32 m. However, since the person can turn at 90Â° after every 10 steps, the maximum displacement is âˆš(32^2 + 32^2) = 16âˆš2 m.

● ● ● ● ●

A truck travelling due north with 20m/s turns towards west and travels at the same speed. Then the change in velocity is -

40 m/s north-west

$20 \sqrt{2}$ m/s north-west

40 m/s south-west

$20 \sqrt{2}$ m/s south-west

You've reached today's free limit of 20 questions. Log in to keep practising for free.

● ● ● ● ●

A particle is moving in a circle of radius r centered at O with constant speed v. The change in velocity moving from A to B $(∠ AOB = 40 °)$ is -

$2 v \cos 40 °$

$2 v \sin 40 °$

$2 v \cos 20 °$

$2 v \sin 20 °$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every Motion in a Lane question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.