Practice free Thermodynamics (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
One mole of a monoatomic ideal gas is mixed with one mole of a diatomic ideal gas The molas specific heat of the micture at constant volume is ..........
$ C_v mix = { n_1 Cv_1 + n_2 Cv_2 \over n_1 + n_2 } $
One mole of a monoatomic gas is heate at a constant pressure of 1 atmosphere from 0k to 100 k. If the gas constant R = 8.32 J/mol k the change in internal energy of the gas is approximate ?
$ \triangle U = \gamma C_v \triangle T $
A monoatomic ideal gas, initially at temperature $T_1 $ is enclosed in a cylindes fitted witha frictionless piston. The gas is allowed to expand adiabatically to a temperature $T_2 $ by releasing the piston suddenly If $L_1$ and $L_2$ the lengths of the gas colum be fore and afters expansion respectively, then $ { T_1 \over T_2} $ is given by
TV = [an adiabatic process] $T_1 V_1 = T_2 V_2 $ $ {T_1 \over T_2 } = \left( { V_2 \over V_1 } \right) $
In a given process on an ideal gas dw = 0 and dQ < 0. Then for the gas
dQ = du + dw
Wafer of volume 2 filter in a containes is heated with a coil of 1kw at $ 27^\circ C $ The lid of the containes is open and energy dissipates at the late of 160 J/S In how much time tempreture will rise from $ 27 ^\circ to 77 ^\circ $. Specific heat of wafers is 4.2 KJ /Kg
energy required in heating water = $ ms \triangle \theta $ from coil, $ { , energy avilable \over S } = Power of coil - Power lost $ For 840 J time required = 1S $ \therefore 4.2 \times 10 ^ {4} J = ? $ $ t = { 4.2 \times 10 ^ 5 \over 840 } 500 J = 8.33 min = 8 min 205 $
70 calorie of heat are required to raise the temperature of 2 mole of an ideal gas at constant pressure from $ 30 ^\circ to 35 ^\circ $ .The amount of heat required to raise the temperature of the same gas through the same range at constant volume is............calorie.
$ C_p = { ( \triangle Q ) P \over r \triangle T }$ cv = cp - R = 7-2 = 5 cal /mol K
When an ideal diatomic gas is heated at constant pressure, the fraction of the heat energy supplied which increases the internal energy of the gas is..
$ { \triangle u \over \triangle Q } = { 1 \over \wp } = { 5 \over 7 } $ $ \triangle u = n C_v \triangle T $ $ \triangle Q = n C_p \triangle T $ $ { \triangle u \over \triangle Q } = { C_v \over C_p } = { 1 \over r } = { 5 \over 7 } $
An insulated containes containing monoatomic gas of molas mass Mo is moving with avelocity, V.If the container is suddenly stopped, find the change in temperature.
$ Decrese in K.E = increase \;in I.E { 1 \over 2} mv^2 = \gamma C_v \triangle T $
The first law of thermodynamics is concerned withthe conservation of
$ \triangle Q = \triangle U + \triangle W $
If heat givento a system is 6 k cal and work done is 6kj. The change in internal energy is ...........KJ.
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