Practice free Work Energy And Power (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A body of mass 6 kg is under a force, which causes a displacement in it given by $ S = { 2 t^3 \over 3} $ (in m). Find the work done by the force in first one seconds.
$ s = { 2t^3 \over 3 } \Rightarrow acceleration a = { d^2 s \over dt^2 } =4t , work W = \int_0^l F ds = \int_0^l mads $
A spring gun of spring constant $ 90 \times 10^2 N / M $ is compressed 4cm by a ball of mass 16g. If the trigger is pulled, calculate the velocity of the ball.
Loss in P.E. of spring = gain in K.E. of ball
A uniform chain of length 2m is kept on a table such that a length of 50cm hangs freely from the edge of the table. The total mass of the chain is 5kg. What is the work done in pulling the entire chain on the table. $(g = 10 m\s^2)$
$ w = { mgl \over 2n^2 }$ where n is, fraction of length of the chain hanging from the table.
A uniform chain of length L ans mass M is lying on a smooth table and one third of its is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is
$ w = { mgl \over 2n^2 }$ (n=3 given)
A block of mass 5 kg is resting on a smooth surface. At what angle a force of 20N be acted on the body so that it will acquired a kinetic energy of 40J after moving 4m
$ Fd cos \theta = { 1 \over 2} mv^2 - {1 \over 2} mu^2 $
Natural length of a spring is 60 cm, and its spring constant is 2000N/m. A mass of 20kg is hung from it. The extension produced in the spring is. $ (g = 9.8 m/s^2) $
$ \therefore x = { F \over K } = { mg \over k} $
The potential energy of a body is given by $ U = A - Bx^2 $ (where x is displacement). The magnitude of force acting on the particle is
$ F = - { du \over dk} $
A uniform chain of length L and mass M is lying on a smooth table and ( 1/4 )th of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is
$ w = { mgl \over 2n^2 } $ ( n = 4 given )
An open knife edge of mass m is dropped from a height h on a wooden floor. If the blade penetrates upto the depth d into the wood, the average resistance offered by the wood to the knife edge is,
$ v^2 - V_0^2 = 2 ad , (v =0 ) and V_0 = \sqrt { 2gh } $ $ \therefore o = ( \sqrt { 2gh} )^2 + 2 (g-a) d \therefore a $
A force $F = Ay^2 + By + C$ acts on a body in the y-direction. The work done by this force during a displacement from y = -a to y = a is
$ W = \int Fdy $ $ = \int _{-a} ^{+2} (Ay^2 +By +C)dy $ $ = \left[ { Ay^3 \over 3} + { By^2 \over 2} + cy \right] _{-a}^{+a} $ $ = { 2Aa^3 \over 3} + 2Ca $
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