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Test if the following equation are dimensionally correct (S = surface tension $ \rho $ = density P = pressure v = volume n = coefficient of viscocity r = radius)
Match list - I with list - II List - I (1) Joule (2) Walt (3) volt (4) Resistivity List - II (a) $ henry \times ampere/sec$ (b) $coulomb \times volt $ (c) $ metre \times ohm$ (d) $ (ampere)^2 \times ohm $
The dimensions of four wires of the same material are given below, in which wire the increase in length will be maximum when the same strain is applied.
$ Y = { F \over A} { L \over l} \Rightarrow l \alpha { l \over A } \alpha {L \over \pi d^2 } $ $ \therefore l \alpha { L \over d^2 } ( As F and Y are constant ) $ The ratio of $ { L \over d^2 } $ is maximum for case CD
On increasing the length by 0.5 mm in a steel wire of length 2 mand area of cross-section $2 mm^2$ the force required is..............$ [ Y for steel = 2.2 \times 10^{11} N/m ] $
$ F = { YAI \over L } $
A stress of $ 3.8 \times 10^8 N m^2 $ is applied to steel rod of length 1 m along its length. Its young's modulus is $ 2 \times 10^ {11} N / m^2 0$. Then what is the elongation produced in the rod in mm ?
$ = { { F \over A} \over {\triangle l \over l} } $ $ given stress 3.18 \times 10^8 N/m^2 $ $ \therefore \triangle l ={ \triangle F /A \over Y } $
A force F is needed to break a copper wire having radius R, The force needed to break a copper wire of radius 2R will be........
Breaking force $ \alpha $ area of crossection of $( \pi r^2 ) $ wire If radius of wire is doubled then breaking force will become four times.
A rubber cord 10m long is suspended vertically. How much does it stretch under its own weight. $( Density of rubber is1500 kg /m^3 , Y = 5 \times 10^ 8 N /m^2 , g = 10 m/s ) $
$ l = { L^2 \over 2 Y } $
If x, longitudinal strain is produced in a wire of young's modulus y then energy stored in the material of the wire per unit volume is..........
Energy stored per unit volume $ = {1 \over 2 } \times stress \times strain $
A steel wire of cross-sectional area $ 3 \times 10^ {-6} m^2 $ can with stand a maximum strain of $ 10 ^ {-3} $ Young's modulus of steel is $ 2 \times 10 ^ {11} N /m^2 $ . The maximum mass the wire can hold is ........$ ( g = 10 m/s^2 ) $
$ Y = { stress \over strain } \Rightarrow Max.strain = { Max.stress \over V}$ $ Max. strain = { mg /A \over Y } $
The young's modulus of a rubber string 8 cm long and density $ 1.5 kg /m^3 $ is $ 5 \times 10^8 N /m^2 $ .What will be the length increase due to its own weight?
$ l = { L^2 dg \over 2 Y } = { (8 \times 10^{-2} )^2 \times 1.5 \times 9.8 \over 2 \times 5 \times 10^8 } = 9.6 \times 10^{-11} m $
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.