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Physics NEET Questions — Free MCQ Practice

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A boat is moving with a velocity 3i + 4j with respect to ground. The water in the river is moving with a velocity – 3i – 4j with respect to ground. The relative velocity of the boat with respect to water is

A.

8j

B.

– 6i – 8j

C.

6i +8j

D.

$5 \sqrt{2}$

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Explanation

Relative velocity = $v_{b w} = v_{b} - v_{w}$ = (3i + 4j) – (– 3i – 4j) = 6i + 8j

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A 150 m long train is moving to north at a speed of 10 m/s. A parrot flying towards south with a speed of 5 m/s crosses the train. The time taken by the parrot the cross to train would be:

A.

30 s

B.

15 s

C.

8 s

D.

10 s

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Explanation

Relative velocity of parrot with respect to train

= $5 - (- 10) = 5 + 10 = 15 m / \sec$

Time taken by the parrot $= \frac{d}{v_{rel.}} = \frac{150}{15} = 10 \sec .$

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A river is flowing from east to west at a speed of 5 m/min. A man on south bank of river, capable of swimming 10m/min in still water, wants to swim across the river in shortest time. He should swim

A.

Due north

B.

Due north-east

C.

Due north-east with double the speed of river

D.

None of these

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A person, aiming to reach the exact opposite point on the other bank of a stream, is swimming with a speed of 0.5 m/s at an angle of 120⁰ with the direction of flow of water. The speed of water in the stream is:

A.

1 m/s

B.

0.5 m/s

C.

0.25 m/s

D.

0.433 m/s

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A thief is running away on a straight road in a jeep moving with a speed of 9 m/s. A police man chases him on a motor cycle moving at a speed of 10 m/s. If the instantaneous separation of jeep from the motor cycle is 100 m, how long will it take for the policemen to catch the thief

A.

1 second

B.

19 second

C.

90 second

D.

100 second

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Explanation

Relative speed of police with respect to thief

$= 10 - 9 = 1 m / s$

Instantaneous separation = 100 m

Time = $\frac{distance}{veclotiy} = \frac{100}{1} = 100 \sec .$

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A man sitting in a bus travelling in a direction from west to east with a speed of 40 km/h observes that the rain-drops are falling vertically down. To the another man standing on ground the rain will appear

A.

To fall vertically down

B.

To fall at an angle going from west to east

C.

To fall at an angle going from east to west

D.

The information given is insufficient to decide the direction of rain.

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A boat takes two hours to travel 8 km and back in still water. If the velocity of water is 4 km/h, the time taken for going upstream 8 km and coming back is

A.

2h

B.

2h 40 min

C.

1h 20 min

D.

Cannot be estimated with the information given

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Explanation

Boat covers distance of 16km in a still water in 2 hours.

i.e. $v_{B} = \frac{16}{2} = 8 k m / h r$

Now velocity of water $\Rightarrow v_{w} = 4 k m / h r$ .

Time taken for going upstream

$t_{1} = \frac{8}{v_{B} - v_{w}} = \frac{8}{8 - 4} = 2 h r$

(As water current oppose the motion of boat)

Time taken for going down stream

$t_{2} = \frac{8}{v_{B} + v_{w}} = \frac{8}{8 + 4} = \frac{8}{12} h r$

(As water current helps the motion of boat)

∴ Total time $= t_{1} + t_{2} = (2 + \frac{8}{12}) h r$ or 2hr 40min

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A 120 m long train is moving towards west with a speed of 10 m/s. A bird flying towards east with a speed of 5 m/s crosses the train. The time taken by the bird to cross the train will be

A.

16 sec

B.

12 sec

C.

10 sec

D.

8 sec

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Explanation

Relative velocity $= 10 + 5 = 15 m / s$ .

Time taken by the bird to cross the train $= \frac{120}{15} = 8 \sec$

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A vector $\vec{a}$ is turned without a change in its length through a small angle $d θ .$ The value of $| Δ \vec{a} |$ and $Δ a$ are respectively

A.

$0, a d θ$

B.

$a d θ, 0$

C.

0, 0

D.

None of these

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Explanation

When a vector is turned through a small angle dÎ¸ without changing its length, the magnitude of the change in the vector (|Î”a|) is a Ã— dÎ¸, where a is the original vector length. The change in the vector (Î”a) itself is perpendicular to the original vector, with a magnitude of a Ã— dÎ¸.

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Two trains along the same straight rails moving with constant speed 60 km/hr and 30 km/hr respectively towards each other. If at time t = 0, the distance between them is 90 km, the time when they collide is

A.

1 hr

B.

2 hr

C.

3 hr

D.

4 hr

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Explanation

The relative velocity $v_{r e l .} = 60 - (- 30) = 90 k m / h r .$

Distance between the train $s_{r e l .} = 90 k m,$

∴ Time when they collide $= \frac{s_{r e l .}}{v_{r e l .}} = \frac{90}{90} = 1 h r .$

Physics MCQs for NEET — Practice Questions with Answers

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