In an electromagnetic wave, if the amplitude of magnetic field is $ 3 \times 10 ^ {-10 } T $ amplitude of the associated electric field will be
In an electromagnetic wave, the relationship between the electric field $(E)$ and the magnetic field $(B)$ is given by $E = cB$, where $c$ is the speed of light in a vacuum $(3 imes 10^8 ext{ m/s})$. Given $B = 3 imes 10^{-10} ext{ T}$, the amplitude of the associated electric field will be $E = 3 imes 10^8 ext{ m/s} imes 3 imes 10^{-10} ext{ T} = 9 imes 10^{-2} ext{ Vm}^{-1}$. Therefore, the correct option is $9 imes 10^{-2} ext{ Vm}^{-1}$.