Physics MCQs for NEET — Practice Questions with Answers

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If the wavelength of light is 4000 $ A ^ \circ $ then the number of waves in 1mm length will

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The SI unit of displacement current is

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Explanation

The SI unit of displacement current is the Ampere (A). Displacement current is a quantity appearing in Maxwell's equations and is defined in terms of the rate of change of the electric field. Since it has the same units as regular current, the unit is Ampere.

The electromagnetic waves do not transport

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Explanation

Electromagnetic waves transport energy, momentum, and information, but they do not transport charge. Charge is a property of particles, not waves. Therefore, the correct option is 'Charge'.

An electric charge oscillating with a frequency of 1kilo cycles/s can radiates electromagnetic waves of wavelength

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The frequency 1057MHz of radiation arising from two close energy levels in hydrogen belongs to

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A plane electromagnetic wave is incident on a material surface. If the wave delivers momentum p and energy E, then

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Explanation

When a plane electromagnetic wave is incident on a material surface, it transfers both energy and momentum. Therefore, both p (momentum) and E (energy) are not zero.

Maxwell’s modified form of Ampere’s circuital law is

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Explanation

Maxwell's modified form of Ampere's circuital law includes the displacement current term and is given by: $$ \oint \\vec B . d \\vec l = \\\mu_0 i + \\\mu_0 \\\varepsilon_0 { \\frac{d \\\\varphi_E}{dt} } $$ This accounts for the changing electric field in addition to the current.

The wavelength of x rays is of the order of

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Explanation

X-rays have wavelengths in the range of $10^{-8}$ to $10^{-12}$ meters. Therefore, the order of magnitude for the wavelength of X-rays is typically around $10^{-10}$ meters.

A point source of electromagnetic radiation has an average output power of 800W. The maximum value of electric field at a distance of 4.0m from the source is

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A plane electromagnetic wave $ E_z = 100 cos ( 6 \times 10^8 t + 4x ) Vm^{-1 } $ propagate in a medium of refractive index

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Explanation

The wave number $k$ and angular frequency $ ext{ω}$ relationship is given by $k = rac{2 ext{π} n}{ ext{λ}}$ and $ ext{ω} = rac{2 ext{π} c}{ ext{λ}}$, where $n$ is the refractive index, $ ext{λ}$ is the wavelength, and $c$ is the speed of light. Given the equation $E_z = 100 ext{cos} (6 imes 10^8 t + 4x)$, we can identify $ ext{ω} = 6 imes 10^8$ rad/s and $k = 4 ext{m}^{-1}$. Using the relation $c = rac{ ext{ω}}{k}$, we find $c = rac{6 imes 10^8 ext{rad/s}}{4 ext{m}^{-1}} = 1.5 imes 10^8 ext{m/s}$. The refractive index $n$ can be calculated using $n = rac{c_{ ext{vacuum}}}{c} = rac{3 imes 10^8 ext{m/s}}{1.5 imes 10^8 ext{m/s}} = 2$.

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