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Physics MCQs for NEET — Practice Questions with Answers

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Five balls numbered 1 to 5 are suspended using separate threads. Pairs (1, 2), (2, 4), and (4, 1) show electrostatic attraction, while pair (2, 3) and (4, 5) show repulsion. Therefore ball 1 must be

Positively charged

Negatively charged

Neutral

Made of metal

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Explanation

(2, 3) and (4, 5) repel each other. It is clear that 2, 3, 4, and 5 are charged bodies. Let (2, 3) have +ve charge and (4, 5) have -ve charge. (1, 2) attract each other. That means ball 1 has -ve charge. But (1, 4) also attract each other. So ball 1 should be neutral. In that case, only, ball 1 can be attracted by both 2 and 4.It means be ball one has no charge so it must negatively charge.

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Two identical conductors of copper and aluminium are placed in an identical electric field. The magnitude of induced charge in the aluminum will be

Zero

Greater than in copper

Equal to that in copper

Less than in copper

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Explanation

Since both are metals so equal amount of charge will induce on them.

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The electric field near a conducting surface having a uniform surface charge density σ is given by

$\frac{σ}{ε_{0}}$ and is parallel to the surface

$\frac{2 σ}{ε_{0}}$ and is parallel to the surface

$\frac{σ}{ε_{0}}$ and is normal to the surface

$\frac{2 σ}{ε_{0}}$ and is normal to the surface

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Explanation

Electric field near the conductor surface is given by $\frac{σ}{ε_{0}}$ and it is perpendicular to surface.

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The magnitude of electric field E in the annular region of a charged cylindrical capacitor

Is same throughout

Is higher near the outer cylinder than near the inner cylinder

Varies as 1/r, where r is the distance from the axis

Varies as 1/r², where r is the distance from the axis

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Explanation

The magnitude of electric field in the annular region of a charged cylindrical capacitor is given by $E = \frac{1}{2 π ε_{0}} \frac{λ}{r}$ where λ is the charge per unit length and r is the distance from the axis of the cylinder. Thus $E \propto \frac{1}{r}$

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A hollow insulated conducting sphere is given a positive charge of 10μC. What will be the electric field at the centre of the sphere if its radius is 2 meters

Zero

5μ Cm^–2

20μ Cm^–2

8μ Cm^–2

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Explanation

The intensity of electric field inside a hollow conducting sphere is zero.

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An electron of mass m_e initially at rest moves through a certain distance in a uniform electric field in time t₁. A proton of mass m_p also initially at rest takes time t₂ to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio of t₂/ t₁ is nearly equal to

${(m_{p} / m_{e})}^{1 / 2}$

${(m_{e} / m_{p})}^{1 / 2}$

1836

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Explanation

For electron $s = \frac{1}{2} \frac{e E}{m_{e}} \times t_{1}^{2}$ , For proton $s = \frac{1}{2} \frac{e E}{m_{p}} \times t_{2}^{2}$

∴ $\frac{t_{2}^{2}}{t_{1}^{2}} = \frac{m_{p}}{m_{e}} \Rightarrow \frac{t_{2}}{t_{1}} = \sqrt{\frac{m_{p}}{m_{e}}} = {(\frac{m_{p}}{m_{e}})}^{1 / 2}$

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Point charges +4q, –q and +4q are kept on the x-axis at points x = 0, x = a and x = 2a respectively, then

Only -q is in stable equilibrium

None of the charges are in equilibrium

All the charges are in unstable equilibrium

All the charges are in stable equilibrium

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Explanation

Force on each charge is zero. But if any of the charge is displaced, the net force starts acting on all of them.

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An electron enters an electric field with its velocity in the direction of the electric lines of force. Then

The path of the electron will be a circle

The path of the electron will be a parabola

The velocity of the electron will decrease

The velocity of the electron will increase

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Explanation

Because electric field applies the force on electron in the direction opposite to it’s motion.

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The dimension of (1/2) $ε_{0} E^{2} (ε_{0}$ : permittivity of free space; E: electric field) is

MLT^–1

ML²L^–2

ML^–1T^–2

ML²T^–1

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Explanation

Energy density $= \frac{Energy}{Volume}$

so it’s dimensions are $\frac{M L^{2} T^{- 2}}{L^{3}} = [M L^{- 1} T^{- 2}]$

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A table tennis ball that has been covered with conducting paint is suspended by a silk thread so that it hangs between two plates, out of which one is earthed and other is connected to a high voltage generator. This ball

Is attracted towards high voltage plate and stays there

Hangs without moving

Swing backward and forward hitting each plate in turn

Is attracted to the earthed plate and stays there

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Explanation

Firstly being a conductor it is attracted by the high voltage plate, when charge is shared, ball is repelled until it goes to other plate and whole of the charge is transferred to the earth and the process is repeated.

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