Physics MCQs for NEET — Practice Questions with Answers

 $\mathrm{E}=\frac{\mathrm{hc}}{\mathrm{\lambda }}$         

$\mathrm{E}=\frac{1}{2}{\mathrm{mu}}^2$

$\mathrm{p}=\frac{\mathrm{E}}{2\mathrm{v}}$         

$\mathrm{E}=\frac{1}{2}{\mathrm{mc}}^2$

Photon exerts no pressure

Photon energy is hv

Photon rest mass is zero

None of these

$\frac{\mathrm{hc}}{\mathrm{E}}$             

$\frac{\mathrm{hv}}{\mathrm{c}}$

 $\frac{\mathrm{hv}}{{\mathrm{c}}^2}$             

hv

 $4.14\times {10}^3 \mathrm{keV}$         

$4.14\times {10}^2 \mathrm{eV}$

$4.14\times {10}^3 \mathrm{MeV}$         

$4.14\times {10}^3 \mathrm{eV}$

 $\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=1$                       

$\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{{\mathrm{\gamma }}_1}{{\mathrm{\gamma }}_2}$

  $\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{{\mathrm{\gamma }}_2}{{\mathrm{\gamma }}_1}$                     

$\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{{\mathrm{\gamma }}_1^2}{{\mathrm{\gamma }}_2^2}$

Kinetic energy of all the emitted electrons

Mean kinetic energy of the emitted electrons

Maximum kinetic energy of the emitted electrons

Minimum kinetic energy of the emitted electrons

Independent of the intensity of illumination

Independent of the frequency of light

Inversely proportional to the intensity of illumination

Directly proportional to the intensity of illumination

50-watt infrared lamp

50-watt ultraviolet lamp

1-watt ultraviolet lamp

Both (b) and (c)

No photoelectric emission takes place

Photo-electrons come out with zero speed

Photo-electrons come out with ${10}^3$ m/sec speed

Photo-electrons come out with ${10}^5$ m/sec speed

Mass-energy relation

Special theory of relativity

Photoelectric equation

(a) and (b) both