Physics MCQs for NEET — Practice Questions with Answers

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Consider the following statements. If the van der Waals' parameters of two gases are given as

                                a/dm6 bar mol-2                               b/dm3 mol-1Gas A                                6.5                                                 0.055Gas B                                  2                                                     0.01

then:

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Pressure remaining the same, the volume of a given mass of an ideal gas increase for every degree centigrade rise in temperature by definite fraction of its volume at:

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Explanation

1.

The volume of a fixed mass of dry gas increases or decreases by ​1273 times the volume at 0 °C for every 1 °C rise or fall in temperature.

The critical temperature of a substance is:

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Explanation

the temperature above which a substance can exist only in gaseous state

 

The excluded volume of a gas will be larger, if TCPC is:

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Explanation

TCPC=8a×27b227Rb×a=8bRVExcluded=nb

  

The correct order of temperature of a real gas is:

(I) Boyle's temperature
(II) Critical temperature
(III) Inversion temperature

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The temperature at which the second virial coefficient of real gas is zero is called:

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However great the pressure, a gas cannot be liquified above its:

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Explanation

3.

Critical Temperature: The temperature which above, a substance can not exist as a liquid, no matter how much pressure is applied. Every substance has a critical temperature.

 

The temperature at which real gases obey the ideal gas laws over a wide range of low pressure is called:

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Explanation

3.

temperature for which the second virial coefficient, becomes 0. It is at this temperature that the attractive forces and the repulsive forces acting on the gas particles balance out.

 

Inversion temperature Ti=2aRb is defined as the temperature above which if gas is expanded adiabatically it gets warm up but if temperature of gas is lower than T, then it will cool down. What will happen to a gas if it is adiabatically expanded at 600 K if its Boyle's temperature is 290 K?

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Explanation

 

It is the temperature at which gas shows neither cooling effect nor heating effect i.e., Joule-Thomson coefficient µ = 1. Below this temperature, it shows cooling effect and above this temperature, it shows heating effect.

Any gas like H2, H­e etc, whose inversion temperature is low would show heating effect at room temperature. However, if these gases are just cooled below inversion temperature and then subjected to Joule-Thomson effect, they will also undergo cooling.

The van der Waal's equation of law of corresponding states for 1 mole of gas is:

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Explanation

The van der Waal's equation for 1 mole of gas is            P+aV2 V-b=RT if we put, Pr=PPC, Vr=VmVc and Tr=TTC;       PC=a27 b2, VC=3b and TC=8a27 RbPra227 b2+aVr23b2 Vr3b-b=RTr 8a27RbThis equation is called van der Waal's equation of law of corresponding states.

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