Physics MCQs for NEET — Practice Questions with Answers

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The work done in bringing a unit positive charge from infinity to a point P in an electric field is called:

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Explanation

By definition, 'V at a point P is the work done in bringing a unit positive charge from infinity to the point P.' (Section 2.8.1). Also confirmed earlier in Section 2.3, 'Potential at P due to the charge Q is $V(r) = \frac{Q}{4\pi\epsilon_0 r}$'.

Why is the concept of potential energy meaningful for electrostatic forces?

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Explanation

The NCERT states, 'The path-independence of work done by an electrostatic field can be proved using the Coulomb’s law... The concept of the potential energy would not be meaningful if the work depended on the path.' (Section 2.2(i)). This highlights the conservative nature of electrostatic forces.

Consider an electric dipole in a uniform electric field. If an external torque $\vec{\tau}_{ext}$ rotates the dipole from an angle $\theta_0$ to $\theta_1$ without angular acceleration, the work done by the external torque is stored as:

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Explanation

The provided text explains: 'The amount of work done by the external torque will be given by $pE (\cos\theta_0 - \cos\theta_1)$. This work is stored as the potential energy of the system.' (Section 2.8.3).

When defining the electrostatic potential energy of a system of charges, why is no work required to bring the first charge ($q_1$) from infinity to its location $r_1$?

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Explanation

In the process of assembling a system of charges, when the first charge ($q_1$) is brought from infinity, there are no other charges yet present in the field to exert any electrostatic force on it. Hence, no work is done against an existing electrostatic field. The NCERT implies this when discussing 'Potential energy of a system of charges' (Section 2.7): 'To bring $q_1$ first from infinity to $r_1$, no work is required.'

Which of the following statements correctly defines the specific heat capacity ($s$) of a substance?

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Explanation

According to the provided text, "The specific heat capacity of a substance is defined by $s = \frac{1}{m} \frac{\Delta Q}{\Delta T}$ where m is the mass of the substance and $\Delta Q$ is the heat required to change its temperature by $\Delta T$." This directly corresponds to option 1.

If $\Delta Q$ is the heat supplied to a substance, $\mu$ is the number of moles, and $\Delta T$ is the change in temperature, which formula represents the molar specific heat capacity ($C$)?

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Explanation

The text states: "The molar specific heat capacity of a substance is defined by $C = \frac{1}{\mu} \frac{\Delta Q}{\Delta T}$ where $\mu$ is the number of moles of the substance." This matches option 1.

What is the primary characteristic of latent heat of fusion ($L_f$)?

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Explanation

The definition provided is: "The latent heat of fusion ($L_f$) is the heat per unit mass required to change a substance from solid into liquid at the same temperature and pressure." This aligns with option 2.

Which of the following best describes the latent heat of vaporisation ($L_v$)?

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Explanation

As per the text: "The latent heat of vaporisation ($L_v$) is the heat per unit mass required to change a substance from liquid to the vapour state without change in the temperature and pressure." This corresponds to option 2.

If the specific heat capacity $s$ is measured in J kg$^{-1}$ K$^{-1}$, what would be the unit for molar specific heat capacity $C$?

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Explanation

The text states: "The unit of C is J mol$^{-1}$ K$^{-1}$." This is consistent with the definition of molar specific heat capacity being per mole, as opposed to specific heat capacity being per unit mass.

Which of the following statements is true regarding the electrostatic potential energy of a system of two charges $q_1$ and $q_2$?

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Explanation

According to the NCERT text, 'the potential energy of a system of two charges $q_1$ and $q_2$ is $U = \frac{1}{4\pi\epsilon_0} \frac{q_1q_2}{r_{12}}$' (Eq. 2.22), which shows direct proportionality to $q_1q_2$ and inverse proportionality to $r_{12}$. Also, 'the potential energy U would be the same... because of path-independence of work for electrostatic force.' Therefore, both (b) and (c) are correct.

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