In the following first order competing reactions:
A + Reagent Product
B + Reagent Product
The ratio of K1/K2 if only 50% of B will have been reacted when 94% of A has been reacted in same time is:
(a) For 50% B reacted, K2 = (2.303/T2)log100/50
For 94% A reacted, K1 = (2.303/T1)log100/6
K2/K1 = t2/t1x0.3010/1.2218
Since t2 = t1, because 50% B has reacted when 94% A has reacted.
K2/K1 = 0.3010/1.2218 = 0.246 and K1/K2 = 4.06