Chemical Thermodynamics MCQs for NEET — Chemistry Questions with Answers

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Predict which of the following reaction(s) has a positive entropy change?

(i) Ag+ (aq) + Cl-(aq) AgCl(s)

(ii) NH4Cl(g) NH3(g) + HCl(g)

(iii) 2NH3(g)N2(g) + 3H2(g)

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Explanation

 ng = (+ve)

 

When two moles of an ideal gas (Cp, m=52R) heated from 300 K to 600 K at constant pressure the change in entropy of gas (S) is:-

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Explanation

 S=nCplnT2T1 + nRlnV2V1

           = 2 x 52Rln(600/300) + 2xRln(2V/V) = 7Rln2

The free energy change G=0 when:-

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Explanation

When G=0              Equilibrium

         G=(+ve)       Non spontaneous

         G=(-ve)        Spontaneous

For isothermal expanison in case of an ideal gas:-

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Explanation

For ideal gas isothermal expansion

H=0G=-TS

At 25°C, for the process H2O(l)H2O(g);

G° is 8.6 kJ. The vapour pressure of water at this temperature is nearly:-

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Explanation

At equilibrium G° = -RTlnKeq

 KeqPH2O/P° and P°= 1 bar

What will be the standard enthalpy of reaction for the following reaction using the listed enthalpies of reaction:-

3Co(s) + 2O2(g)Co3O4(s);       H=?

2Co(s) + O2(g) 2CoO(s)          H1= -475.8 KJ

6CoO(s) + O2(g) 2Co3O4(s)     H2 = -355.0 KJ

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Explanation

H°=32H1° + H2°2

       = -713.7 - 177.5 = -891.2 KJ

For given following equations and H° values determine the enthalpy of reaction at 298 K for the reaction 

C2H4(g) + 6F2(g)  2CF4(g) + 4HF(g)

H2(g) + F2(g)  2HF(g)       H1°= -537 kJ

C(s) + 2F2(g) CF4(g)         H2°=-680 kJ

2C(s) + 2H2(g) C2H4(g)    H3°= 52 kJ

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Explanation

 H°=2H1° + 2xH2°-H3°

If Hf°(C2H4) and Hf°(C2H6) are x1 and x2 kcal/mol then heat of hydrogenation of C2H4 is :-

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Explanation

3. Target reaction C2H4 + H2 C2H6

Given reaction

(i) 2C + 2H2 C2H4    H1=x1

(ii) 2C + 3H2C2H6    H2= x2

(ii)-(i) = x2 - x1

For oxidation of iron, 4Fe(s) + 3O2(g) 2Fe2O3(s), Hr°=-1648x103 J mol-1 entropy change is:

-549.4 J k-1mol-1 at 298 K:-

The reaction is

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Explanation

ST=Ssystem+SSurr.       = + ve

18 g of ice is converted into water at 0°C and 1 atm. The entropy of H2O(s) and H2O(l) are 38.2 and 60 J K-1 mol-1 respectively. the enthalpy for this conversion will be

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Explanation

 Sr= 60-38.2=21.8 JK-1 mol-1

        ..H=21.8 x 273 = 5951.4 J/mol

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