Chemical Thermodynamics MCQs for NEET — Chemistry Questions with Answers

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Predict which of the following reaction(s) has a positive entropy change?

(i) Ag+ (aq) + Cl-(aq) →AgCl(s)

(ii) NH4Cl(g) →NH3(g) + HCl(g)

(iii) 2NH3(g)→N2(g) + 3H2(g)

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Explanation

 ∆ng = (+ve)

 

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When two moles of an ideal gas (Cp, m=52R) heated from 300 K to 600 K at constant pressure the change in entropy of gas (∆S) is:-

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Explanation

 ∆S=nCplnT2T1 + nRlnV2V1

           = 2 x 52Rln(600/300) + 2xRln(2V/V) = 7Rln2

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The free energy change ∆G=0 when:-

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Explanation

When ∆G=0              Equilibrium

         ∆G=(+ve)       Non spontaneous

         ∆G=(-ve)        Spontaneous

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For isothermal expanison in case of an ideal gas:-

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Explanation

For ideal gas isothermal expansion

∆H=0∆G=-T∆S

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At 25°C, for the process H2O(l)⇌H2O(g);

∆G° is 8.6 kJ. The vapour pressure of water at this temperature is nearly:-

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Explanation

At equilibrium ∆G° = -RTlnKeq

 Keq = PH2O/P° and P°= 1 bar

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What will be the standard enthalpy of reaction for the following reaction using the listed enthalpies of reaction:-

3Co(s) + 2O2(g)→Co3O4(s);       ∆H=?

2Co(s) + O2(g) →2CoO(s)          ∆H1= -475.8 KJ

6CoO(s) + O2(g) →2Co3O4(s)     ∆H2 = -355.0 KJ

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Explanation

∆H°=32∆H1° + ∆H2°2

       = -713.7 - 177.5 = -891.2 KJ

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For given following equations and ∆H° values determine the enthalpy of reaction at 298 K for the reaction 

C2H4(g) + 6F2(g) → 2CF4(g) + 4HF(g)

H2(g) + F2(g) → 2HF(g)       ∆H1°= -537 kJ

C(s) + 2F2(g) →CF4(g)         ∆H2°=-680 kJ

2C(s) + 2H2(g) →C2H4(g)    ∆H3°= 52 kJ

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Explanation

 ∆H°=2∆H1° + 2x∆H2°-∆H3°

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If ∆Hf°(C2H4) and ∆Hf°(C2H6) are x1 and x2 kcal/mol then heat of hydrogenation of C2H4 is :-

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Explanation

3. Target reaction C2H4 + H2 →C2H6

Given reaction

(i) 2C + 2H2 →C2H4    ∆H1=x1

(ii) 2C + 3H2→C2H6    ∆H2= x2

(ii)-(i) = x2 - x1

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For oxidation of iron, 4Fe(s) + 3O2(g) →2Fe2O3(s), ∆Hr°=-1648x103 J mol-1 entropy change is:

-549.4 J k-1mol-1 at 298 K:-

The reaction is

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Explanation

∆ST=∆Ssystem+∆SSurr.       = + ve

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18 g of ice is converted into water at 0°C and 1 atm. The entropy of H2O(s) and H2O(l) are 38.2 and 60 J K-1 mol-1 respectively. the enthalpy for this conversion will be

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Explanation

 ∆Sr= 60-38.2=21.8 JK-1 mol-1

        ... ∆H=21.8 x 273 = 5951.4 J/mol

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