Which of the following aqueous solution should have the highest osmotic pressure?
π = iCRT T ↑ , T ↑ so, π ↑
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Which of the following aqueous solution should have the highest osmotic pressure?
π = iCRT T ↑ , T ↑ so, π ↑
50 g of antifreeze (ethylene glycol) is added to 200g water. What amount of ice will separate out at
-9.3°C. (Kf = 1.86 K Kg mol-1) :-
ΔTf = 1000 Kf w ⇒ 9.3 = 1000 x 1.86 x 50
mW 62 x W
⇒ W= 161.29g
Separated ice= 200-161.29= 38.71g
40 g NaOH (i=2) is dissolved in 1L volatile solvent vapour pressure of this solution becomes equal to its solid phase at 300K. What is the freezing point of pure solvent.
(Density = 1g/mL) (kf=1.8 k kgmol-1)
Tf = iKfm
Tf - 300 = 2x1.8x(40/40)/1
Tf = 303.6K
100 g solute is dissolved in 1400 g of solvent. Density of resultant solution is 1.5 g/mL. The ratio of its molarity and molality will be :-
The molarity of the solution is given by the number of moles of solute divided by the volume of the solution in liters. The molality is given by the number of moles of solute divided by the mass of the solvent in kilograms. Since the density of the solution is 1.5 g/mL, the ratio of molarity to molality will be (1.5 g/mL) / (1000 g/kg) = 1.4.
As scuba divers come towards water surface from underwater, solubility of gases in their blood :-
According to Henry‘s law, solubility Partial directly proportional to the pressure.
Saturated solution of Ag2SO4 shows 0.003K rise in boiling point, Ksp will be :(Kb = 5 K kg mol-1)(1m=1M)
Tb = iKbm
0.003=3x5xS
S=2x10-4
Ksp = 4S3=3.2x10-11
When 36 g of a solute having the empirical formula CH2O is dissolved in 1.2 kg of water, the solution freezes at
-0.93°C. What is the molecular formula of solute (Kf = 1.86 kg K mol-1)
ΔTf= i Kf m
0.93= 1 x 1.86 x 36/M ; M=60
1.2
A solution containing 0.03659 g/ml of HCl and a solution containing 0.04509 g/ml of acetic acid Then:
NHCl=
The relative lowering of vapour pressure caused by dissolving 71.3 g of a substance in 1000 g of water is 7.13 X 10-3. The molecular mass of the substance is :-
Total vapour pressure of mixture of 1mol and 2 mol is 200 torr. In this case:
The total vapor pressure of the mixture is less than the sum of the vapor pressures of the pure components (150 torr for A and 240 torr for 2 mol of B), which indicates a negative deviation from Raoult's law. This suggests that there are attractive intermolecular forces between A and B molecules, leading to a lower vapor pressure than expected.
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