A transformer has an efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A the voltage across the secondary coil and the current in the primary coil respectively are:
Current in primary coil = P/V = 3000/200 = 15A
efficiency is 90%
So output power is 90% of input
Po = (90/100)x3000
If output voltage and current - VoIo
VoIo =(90/100)x3000
Vox6=(90/100)x3000
Vo = 450 V