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Laws of Motion MCQs for NEET — Physics Questions with Answers

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A body is imparted motion from rest to move in a straight line. If it is then obstructed by an opposite force, then

The body may necessarily change direction

The body is sure to slow down

The body will necessarily continue to move in the same direction at the same speed

None of these

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Explanation

Opposite force causes retardation.

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A second's pendulum is mounted in a rocket. Its period of oscillation decreases when the rocket

Comes down with uniform acceleration

Moves round the earth in a geostationary orbit

Moves up with a uniform velocity

Moves up with uniform acceleration

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Explanation

$T = 2 π \sqrt{\frac{l}{g_{e f f}}}$ . T will decrease, if $g_{e f f}$ increases.

It is possible when rocket moves up with uniform acceleration a. Then $g_{e f f}$ = g + a

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Two balls of masses m₁ and m₂ are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly the powder charge explodes and masses are pushed apart. The mass m₁ travels a distance s₁ and stops. If the coefficients of friction between the balls and ground are same, the mass m₂ stops after travelling the distance

$s_{2} = \frac{m_{1}}{m_{2}} s_{1}$

$s_{2} = \frac{m_{2}}{m_{1}} s_{1}$

$s_{2} = \frac{m_{1}^{2}}{m_{2}^{2}} s_{1}$

$s_{2} = \frac{m_{2}^{2}}{m_{1}^{2}} s_{1}$

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A force vector applied on a mass is represented as $\vec{F} = 6 \hat{i} - 8 \hat{j} + 10 \hat{k}$ and accelerates with 1 m/s². What will be the mass of the body

$10 \sqrt{2} k g$

$2 \sqrt{10} k g$

10 kg

20 kg

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Explanation

$m = \frac{F}{a} = \frac{\sqrt{6^{2} + 8^{2} + 10^{2}}}{1} = \sqrt{200} = 10 \sqrt{2} k g$

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A cricket ball of mass 250 g collides with a bat with velocity 10 m/s and returns with the same velocity within 0.01 second. The force acted on bat is

25 N

50 N

250 N

500 N

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Explanation

Force $= m (\frac{d v}{d t}) = \frac{0 .25 \times [(10) - (- 10)]}{0 .01} = 25 \times 20 = 500 N$

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A pendulum bob of mass 50 gm is suspended from the ceiling of an elevator. The tension in the string if the elevator goes up with uniform velocity is approximately

0.30 N

0.40 N

0.42 N

0.50 N

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Explanation

$T = m g = 50 \times 10^{- 3} \times 10 = 0 .5 N$

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The average force necessary to stop a bullet of mass 20 g moving with a speed of 250 m/s, as it penetrates into the wood for a distance of 12 cm is

2.2 × 10³ N

3.2 × 10³ N

4.2 × 10³ N

5.2 × 10³ N

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Explanation

$u = 250 m / s$ , $v = 0$ , $s = 0 .12 m e t r e$

$F = m a = m (\frac{u^{2} - v^{2}}{2 s}) = \frac{20 \times 10^{- 3} \times {(250)}^{2}}{2 \times 0 .12}$

∴ $F = 5 .2 \times 10^{3} N$

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A man measures time period of a pendulum (T) in stationary lift. If the lift moves upward with acceleration $\frac{g}{4},$ then new time period will be

$\frac{2 T}{\sqrt{5}}$

$\frac{\sqrt{5} T}{2}$

$\frac{\sqrt{5}}{2 T}$

$\frac{2}{\sqrt{5} T}$

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Explanation

$T = 2 π \sqrt{\frac{l}{g}}$ ⇒ $\frac{T^{'}}{T} = \sqrt{\frac{g}{g^{'}}} = \sqrt{\frac{g}{g + \frac{g}{4}}} = \sqrt{\frac{4}{5}} = \frac{2}{\sqrt{5}}$

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If rope of lift breaks suddenly, the tension exerted by the surface of lift (a = acceleration of lift)

m(g + a)

m(g – a)

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Explanation

If rope of lift breaks suddenly, acceleration becomes equal to g so that tension, $T = m (g - g) = 0$

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A lift of mass 1000 kg is moving with an acceleration of 1 m/s² in upward direction. Tension developed in the string, which is connected to the lift, is

9,800 N

10,000 N

10,800 N

11,000 N

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Explanation

$T = m (g + a) = 1000 (9 .8 + 1) = 10800 N$

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