Practice free Laws of Motion (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A player caught a cricket ball of mass 150 g moving at the rate of $20 ms^{-1} $ . If the catching process be completed in 0.1 s the force of the blow exerted by the ball on the hands of player is
Force exerted by ball, F = m (dv /dt)
A body of mass 5 kg starts from the origin with an initial velocity $ \vec u = 30 \hat i + 40 \hat j ms^{-1} $. If a constant Force
$ \vec F = - \left( \hat i + 5 \hat j \right) N $
acts on the body, the time in which the y-component of the velocity becomes
$ \nu_y = 40ms^{-1} Fy = -5N m = 5kg $ $ so a_y = { F_y \over m } = -1 ms^{-1} $ $ as V_y = u_y + at $ $ 0 = 40 -lt \Rightarrow t = 40 s $
A cold soft drink is kept on the balance.When the cap is open, then the weight
Gas will cane out with sufficient speed in forward direction, So recetion of this forward force wil change the reading of the spring balance.
A wagon weighing 1000 kg is moving with a velocity $50 km h^{-1}$ on smooth horizontal rails. A mass of 250 kg is dropped into it. The velocity with which it moves now is
According to the principle of conservation of linear momentum $ 1000 \times 50 = {1250 \times \nu \over \nu} = 40 km/h $
A 7 kg object is subjected to two forces (in newton) $ \vec F _1 = 20 \hat i + 30 \hat j $ and $ \vec F_2 = 8 \hat i -5 \hat j $. The magnitutde of resulting acceleration in $ ms^{-2} $ will be
$ \vec F = \vec F_1 + \vec F_2 $ $ \therefore a = F /m $
A given object takes n times more time to slide down $ 45 ^\circ $ rough inclined plane as it takes to slide down a perfactly smooth $ 45 ^\circ $ incline. The coefficient of kinetic friction between the object and the incline is
$ S = ut + { 1 \over 2 } at^2 $ $as u = 0 ,t = \sqrt { 2S \over a } $ for smooth plane $a = gsin \theta $ For rough plane$ a^1= g (sin \theta -\mu cos \theta)$ $ \therefore t^1 = \sqrt { 2S \over g ( sin \theta - \mu cos \theta ) } $ $ \therefore t^1 = nt = n \sqrt { 2S \over g sin \theta } $ $ \therefore n^2 g (sin \theta - \mu cos \theta) = g sin \theta $ $ when \theta = 45 sin \theta = cos \theta = { 1 \over \sqrt 2 } $ $ \therefore = 1 - { 1 \over n^2 } $
Two bodies of equal masses revolve in circular orbits of radii R1 and R2 with the same period Their centripetal forces are in the ratio
$ F + { mv^2 \over R } = { m(R \omega )^2 \over R } = mR \left({ 2 \pi \over T } \right) ^2 = { 4 \pi ^2 m R \over T^2 } $ As m and T are same for two bodies $ F \alpha R $
A 0.5 kg ball moving with a speed of $12 ms^{-1} $ strikes a hard wall at an angle of 300 with the wall. It is reflected with the same speed and at the same angle. If the ball is in contact with the wall for 0.025 S the average force acting on the wall is
As impulse = change in linear momentum $ Ft = 2 mv sin 30 \Rightarrow F = { 2 m \vartheta sin 30 \over t } $
A shell of mass 200g is ejected from a gun of mass 4 kg by an explosion that generates 1.05 KJ of energy. The initial velocity of the shell is
$ m_1 v_1 + m_2 v_2 = 0 $ $ v_2 = { m_1 \over m_2 } v_1 = - { v_1 \over 20 } $ Now $ E = { 1 \over 2 } m_1 v_1^2 + {1 \over 2 } m_2 v_2^2 $ By solving weight $ \nu_1 = 100 ms^{-1} $
A gramophone record is revolving with an anguler velocity $ \omega $. A coin is placed at a distance r from the centre of the record. The coefficient of static friction is . The coin will revolve with the record if
The coin will revolve with the record if centrifugal force $ mrw^2 \lt f $ $ \therefore mr \omega^2 \lt R \lt mg $ $ r \lt { g \over \omega ^2 } $
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