Practice free Laws of Motion (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A stone of mass 2 k g is tied to a string of length 0.5 m It the breaking tension of the string is 900N, then the maximum angular velocity the stone can have in uniform circular motion is
$ F = mr \omega^2 \Rightarrow \omega = \sqrt { F /mr } = 30 rad/s $
A sparrow flying in air sits on a stretched telegraph wire. If the weight of the sparrow is W ,which of the following is true about the tension T produced in the wire?
When the sparrow sits on the wire, it causes a deflection in the wire, creating a vertical component of tension. The tension in the wire must counteract not only the weight of the sparrow but also the additional vertical components due to the deflection. Therefore, the tension T in the wire is greater than the weight W of the sparrow: $T > W$.
A body of mass 0.05 kg is falling with acceleration $ 9.4 ms^{–2} $ . The force exerted by air opposite to motion is …………. N $(g=9.8 ms^{–2})$
Fair = m ( g - a)
The average force necessary to stop a hammer with 25 NS momentun in 0.04 sec is ………... N
$ F = { \triangle P \over \triangle t } = { 25 \over 0.04 } = 625 N $
Newton's third law of motion leads to the law of consrevation of
Newton's third law of motion states that for every action, there is an equal and opposite reaction. This principle is fundamental to the conservation of momentum. When two bodies interact, the forces they exert on each other are equal in magnitude and opposite in direction, leading to the total momentum of the system remaining constant if no external forces are acting on it.
A ball falls on surface from 10 m height and rebounds to 2.5 m. If duration of
contact with floor is 0.01 sec. then average aceleration during
contact is _ __ ___$ms^{-2} $
$ \nu_o = \sqrt { 2 g h_1 } and \nu = \sqrt {2 g h_1 }$ $ madt = m ( \nu_2 + \nu_1 ) $ $ \therefore a = { \nu_2 + \nu_1 \over dt }$
A vehicle of 100 kg is moving with a velocity of 5 m / s . To stop it in 1/10 sec, the required force in opposite direction is ____ ____ N
To solve this, we use the formula for force, which is given by Newton's second law: \( F = ma \). Here, \( m \) is the mass of the vehicle (100 kg) and \( a \) is the acceleration. First, we need to find the acceleration, which is given by: \( a = \frac{\Delta v}{\Delta t} \). The change in velocity (\( \Delta v \)) is \( -5 \ \text{m/s} \) (since the vehicle is stopping), and the time (\( \Delta t \)) is \( \frac{1}{10} \ \text{s} \). Therefore, \( a = \frac{-5}{1/10} = -50 \ \text{m/s}^2 \). Now, applying Newton's second law: \( F = 100 \ \text{kg} \times -50 \ \text{m/s}^2 = -5000 \ \text{N} \). The negative sign indicates direction, but the magnitude of the force is 5000 N.
The linear momentum P of a particle varies with the time as follows $ P = a + bt^2 $ . Where a and b a re constants. The net force acting on the particle is
$ F = { dp \over dt } = 0 + 2 bt $ $ \therefore F \alpha t $
which of the following statement is correct?
A body with constant speed and zero acceleration means it is moving in a straight line with uniform motion. In uniform motion, both speed and velocity are constant, and the acceleration is zero. Therefore, the correct statement is: “A body has a constant speed and zero acceleration.â€
A force of 8 N acts on an object of mass 5kg in X- direction and another force of 6 N acts on it in Y - direction. Hence, the magnitude of acceleration of object will be
$ F = \sqrt { F_1^2 + F_2^2 } $ $ and a = { F/M } $
Ready to ace NEET?
Free access · No credit card required
Yes. You can attempt every Laws of Motion question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.