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Measurement MCQs for NEET — Physics Questions with Answers

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The dimensions of physical quantity X in the equation Force $= \frac{X}{Density}$ is given by

$M^{1} L^{4} T^{- 2}$

$M^{2} L^{- 2} T^{- 1}$

$M^{2} L^{- 2} T^{- 2}$

$M^{1} L^{- 2} T^{- 1}$

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Explanation

[X] = [F] × [ $ρ$ ] = $[M L T^{- 2}] \times [\frac{M}{L^{3}}] = [M^{2} L^{- 2} T^{- 2}]$

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The dimensions of CV² matches with the dimensions of

L²I

L²I ²

LI²

$\frac{1}{L I}$

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Explanation

Both are the formula of energy . $(E = \frac{1}{2} C V^{2} = \frac{1}{2} L I^{2})$

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The Martians use force (F), acceleration (A) and time (T) as their fundamental physical quantities. The dimensions of length on Martians system are

FT²

$F^{- 1} T^{2}$

$F^{- 1} A^{2} T^{- 1}$

AT²

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Explanation

Acceleration = $\frac{distance}{{time}^{2}}$

$\Rightarrow A = L T^{- 2} \Rightarrow L = A T^{2}$

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The dimension of $\frac{1}{\sqrt{ε_{0} μ_{0}}}$ is that of

Velocity

Time

Capacitance

Distance

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Explanation

$\frac{1}{\sqrt{ε_{0} μ_{0}}} = C =$ velocity of light

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An athletic coach told his team that muscle times speed equals power. What dimensions does he view for muscle

$M L T^{- 2}$

$M L^{2} T^{- 2}$

MLT²

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Explanation

According to problem muscle × speed = power

$∴$ muscle = $\frac{power}{speed} = \frac{M L^{2} T^{- 3}}{L T^{- 1}}$ = $M L T^{- 2}$

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The dimensional formula of wave number is

$M^{0} L^{0} T^{- 1}$

$M^{0} L^{- 1} T^{0}$

$M^{- 1} L^{- 1} T^{0}$

$M^{0} L^{0} T^{0}$

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Explanation

Wave number = $\frac{1}{λ}$

$∴$ dimension is $[M^{0} L^{- 1} T^{0}]$

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The dimensions of stress are equal to

Force

Pressure

Work

$\frac{1}{Pressure}$

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Explanation

[Pressure] =[stress] = $[M L^{- 1} T^{- 2}]$

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The dimensions of pressure are

$M L T^{- 2}$

$M L^{- 2} T^{2}$

$M L^{- 1} T^{- 2}$

$M L T^{2}$

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Explanation

$M L^{- 1} T^{- 2}$

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Dimensions of permeability are

$A^{- 2} M^{1} L^{1} T^{- 2}$

$M L T^{- 2}$

$M L^{0} T^{- 1}$

$A^{- 1} M L T^{2}$

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Explanation

$F = \frac{μ_{0}}{4 π} \frac{2 I_{1} I_{2} l}{r}$ $\Rightarrow μ_{0} = [F] {[A]}^{- 2} = [M L T^{- 2} A^{- 2}]$

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Dimensional formula of magnetic flux is

$M L^{2} T^{- 2} A^{- 1}$

$M L^{0} T^{- 2} A^{- 2}$

$M^{0} L^{- 2} T^{- 2} A^{- 3}$

$M L^{2} T^{- 2} A^{3}$

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Explanation

$φ = B A = \frac{F}{I \times L} A = \frac{[M L T^{- 2}] [L^{2}]}{[A] [L]} = [M L^{2} T^{- 2} A^{- 1}]$

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