Measurement NEET Questions — Free MCQ Practice

Measurement MCQs for NEET — Physics Questions with Answers

Practice free Measurement (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

● ● ● ● ●

If P represents radiation pressure, c represents speed of light and Q represents radiation energy striking a unit area per second, then non-zero integers x, y and z such that $P^{x} Q^{y} c^{z}$ is dimensionless, are

$x = 1, y = 1, z = - 1$

$x = 1, y = - 1, z = 1$

$x = - 1, y = 1, z = 1$

$x = 1, y = 1, z = 1$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

By substituting the dimension of given quantities ${[M L^{- 1} T^{- 2}]}^{x} {[M T^{- 3}]}^{y} {[L T^{- 1}]}^{z} = {[M L T]}^{0}$

$x + y = 0 - (i) - x + z = 0 - (ii) - 2 x - 3 y - z = 0 - (iii) We will try to express y and z in terms of x & substitute in (iii) From (i) y = - x From (ii) z = x Also comparing these 2 euqation z = - y Putting in (iii) - 2 x - 3 (- x) - x = 0 3 x - 3 x = 0 0 = 0$

As you can see, in equation (iii) everything is cancelling. We need one more equation to find values. But if one variable is given, others can be found.

$Ex : If x = 1 Then z = 1 and y = - 1 So in Question, if options are, for values of x, y and z (1) 1, 1, - 1 (2) 1, - 1, 1 (3) - 1, 1, 1 (4) 1, 1, 1 Then option (2) is correct .$

● ● ● ● ●

Inductance L can be dimensionally represented as

$M L^{2} T^{- 2} A^{- 2}$

$M L^{2} T^{- 4} A^{- 3}$

$M L^{- 2} T^{- 2} A^{- 2}$

$M L^{2} T^{4} A^{3}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$E = \frac{1}{2} L i^{2}$ hence $L = [M L^{2} T^{- 2} A^{- 2}]$

● ● ● ● ●

Dimensions of strain are

$M L T^{- 1}$

$M L^{2} T^{- 1}$

$M L T^{- 2}$

$M^{0} L^{0} T^{0}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Strain is dimensionless.

● ● ● ● ●

Dimensions of time in power are

$T^{- 1}$

$T^{- 2}$

$T^{- 3}$

T⁰

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Dimensions of power is $[M L^{2} T^{- 3}]$

● ● ● ● ●

Dimensional formula for torque is

$L^{2} M T^{- 2}$

$L^{- 1} M T^{- 2}$

$L^{2} M T^{- 3}$

$L M T^{- 2}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Torque = force × distance = $[M L^{2} T^{- 2}]$

● ● ● ● ●

Dimensions of coefficient of viscosity are

$M L^{2} T^{- 2}$

$M L^{2} T^{- 1}$

$M L^{- 1} T^{- 1}$

MLT

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$F = - η . A \frac{d v}{d x} \Rightarrow [η] = [M L^{- 1} T^{- 1}]$

● ● ● ● ●

The dimension of quantity (L/RCV) is

[A]

[A²]

$[A^{- 1}]$

None of these

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$\frac{L}{R C V} = [\frac{L}{R}] \frac{1}{C V} = \frac{T}{Q} = [A^{- 1}]$

● ● ● ● ●

The dimension of the ratio of angular to linear momentum is

$M^{0} L^{1} T^{0}$

$M^{1} L^{1} T^{- 1}$

$M^{1} L^{2} T^{- 1}$

$M^{- 1} L^{- 1} T^{- 1}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$\frac{Angular momentum}{Linear momentum} = \frac{m v r}{m v} = r = [M^{0} L^{1} T^{0}]$

● ● ● ● ●

The pair having the same dimensions is

Angular momentum, work

Work, torque

Potential energy, linear momentum

Kinetic energy, velocity

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Dimension of work and torque = $[M L^{2} T^{- 2}]$

● ● ● ● ●

The dimensions of surface tension are

$M L^{- 1} T^{- 2}$

$M L T^{- 2}$

$M L^{- 1} T^{- 1}$

$M T^{- 2}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Surface tension = $\frac{Force}{Length} = \frac{[M L T^{- 2}]}{L} = [M T^{- 2}]$

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every Measurement question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.