A material has poisson's ratio 0.50. If uniform rod of it suffers a longitudinal strain of $ 2 \times 10 ^ {-3} $ Then what is percentage change in volume ?
$$ {dv \over v } = ( 1 + 2 \sigma) {dL \over L } $$ $\therefore {dv \over v } = 2 \times 2 \times 10^{-3} = 4 \times 10 ^ {-3} $ $ [ 6 = 0.5 { 1 \over 2 } ] $