The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of $ 30 ^\circ $ . Then what is the angle of shear ?
Angle of shear $ \phi = { r \theta \over L } = { 4 \times 10^{-1} \over 100 \times 30' } = 0.12 ' $