Semiconductor Electronics: Materials, Devices and Simple Circuits MCQs for NEET — Physics Questions with Answers

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The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is 10 V. The dc component of the output voltage is 

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Explanation

(b) In half wave rectifier Vdc=V0π=10π

The contribution in the total current flowing through a semiconductor due to electrons and holes are 34 and 14 respectively. If the drift velocity of electrons is 52 times that of holes at this temperature, then the ratio of concentration of electrons and holes is

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Explanation

(a) As we know current density J=nqv

Je=neqve  and Jh=nhqvhJeJh=nenh×vevh3/41/4=nenh×520nenh=65

Metals have conductivity of the order of (ohm-1 cm-1):-

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Explanation

(b) The conductance order of metals is 106 to 108 ohm-1 cm-1.

With which one of the following elements silicon should be doped so as to give p-type of semiconductor?

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Explanation

(d) The n-type semiconductors are obtained when Si or Ge are doped with elements of group 15, eg, arsenic (As), while p-type semiconductors are obtained when Si or Ge are doped witlh traces of elements of group 13, ie, indium (In), boron (B).

Note : The conductivity of semiconductors increases with rise in temperature

In the energy band diagram of an n-type silicon semiconductor at room temperature, where is the donor energy level ($E_D$) located relative to the conduction band ($E_C$)?

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Explanation

According to the NCERT text, 'In the energy band diagram of n-type Si semiconductor, the donor energy level $E_D$ is slightly below the bottom $E_C$ of the conduction band and electrons from this level move into the conduction band with very small supply of energy.' This placement facilitates electron donation to the conduction band.

For a p-type semiconductor, what is the location of the acceptor energy level ($E_A$) relative to the valence band ($E_V$)?

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Explanation

The NCERT states, 'for p-type semiconductor, the acceptor energy level $E_A$ is slightly above the top $E_V$ of the valence band... With very small supply of energy an electron from the valence band can jump to the level $E_A$ and ionise the acceptor negatively.' This creates holes in the valence band, which are majority carriers in a p-type semiconductor.

In n-type semiconductors at room temperature, what is the primary source of electrons in the conduction band?

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Explanation

The context mentions, 'at room temperature, most of the donor atoms get ionised but very few (~10^12) atoms of Si get ionised. So the conduction band will have most electrons coming from the donor impurities.' This highlights that doping is the dominant source of conduction electrons in n-type semiconductors.

At room temperature, in a p-type extrinsic semiconductor, what primarily determines the density of holes in the valence band?

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Explanation

The NCERT text explains, 'At room temperature, most of the acceptor atoms get ionised leaving holes in the valence band. Thus at room temperature the density of holes in the valence band is predominantly due to impurity in the extrinsic semiconductor.'

How does doping affect the intrinsic concentration of minority carriers in an extrinsic semiconductor?

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Explanation

The NCERT states, 'In extrinsic semiconductors, because of the abundance of majority current carriers, the minority carriers produced thermally have more chance of meeting majority carriers and thus getting destroyed. Hence, the dopant, by adding a large number of current carriers of one type, which become the majority carriers, indirectly helps to reduce the intrinsic concentration of minority carriers.'

What is the primary reason that electrons from the donor energy level ($E_D$) in an n-type semiconductor can move into the conduction band ($E_C$) with minimal energy supply?

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Explanation

The passage confirms, 'the donor energy level $E_D$ is slightly below the bottom $E_C$ of the conduction band and electrons from this level move into the conduction band with very small supply of energy.' This small energy difference makes it easy for electrons to transition.

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