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Chemical Bonding and Atomic Structure MCQs for NEET — Chemistry Questions with Answers

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In buta 1, 3 - diene

only one sp hybridised carbon atom

only $sp^2$ hybridised carbon atoms

Two $sp^3$ and two $sp^2$ hybridised carbon atoms

$ sp, sp^2 $ and $ sp^3 $ hybridized carbon atoms

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Which of the following statement is irrelevant for sigma bond ?

A. strength of sigma bond is not related with overlapping of atomic orbitals. B. o - bond can form by overlapping of S - P orbitals. C. o - bond can form by overlapping of end of atomic orbitals of inner center axis. D. This type of overlapping is also known as axial overlapping

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Explanation

The strength of a sigma bond is indeed related to the overlapping of atomic orbitals. A stronger sigma bond is formed due to greater overlap between atomic orbitals. Therefore, the statement 'strength of sigma bond is not related with overlapping of atomic orbitals' is irrelevant.

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In which molecule inter molecular hydrogen bond can be form ?

A. methanol B. ethylene glycol C. p - nitrophenol D. phenol

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Which of the following pair possesses very strong H - bond ?

A. $CH_3 COCH_3 and CHCl_3$ B. $HCOOH and CH_3 COOH$ C. $H_2O and H_2$ D. $SiH_4 and SiCl_4$

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Explanation

Formic acid (HCOOH) and acetic acid (CH_3COOH) both have the ability to form strong hydrogen bonds due to the presence of highly electronegative oxygen atoms bonded to hydrogen. This results in a very strong hydrogen bond between these molecules.

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Which of the following relation is correct ?

A. $ Bond order \alpha Bond energy \alpha Bond length \alpha stability $ B. $ Bond order \alpha { 1 \over Bond length } \alpha { 1 \over energy} \alpha stability $ C. $ Bond order \alpha Bond energy \alpha { 1 \over Bond lenght} \alpha stability $ D. $ Bond order \alpha { 1 \over Bond length } \alpha { 1 \over Bond energy} \alpha stability $

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Explanation

The correct relation is: Bond order is directly proportional to bond energy and inversely proportional to bond length. This means higher bond order indicates greater bond energy and shorter bond length, contributing to the stability of the molecule. Therefore, the relation is $Bond order \alpha Bond energy \alpha {1 \over Bond length} \alpha stability$.

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Which of the following is correct?

In PF5, axial and equatorial bonds are interchanged, known as pseudoreaction

In solid state PF5 remains covalent

PH5 cannot be obtained, because H is not sufficiently electronegative to make the d-orbitals contact
sufficiently

All of these

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Explanation

factual

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In water bond angle is $104 ^\circ 30 $ because

Oxygen atom is $sp^3$ hybridised

Repulsion between lone pair election and bonding pair electron

Oxygen has high electronegetivity.

$H_2O$ molecule possesses ''V'' - shape.

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Explanation

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In which of the following strong H-bond is present ?

A. F - H.....F B. O - H.....N C. O - H.....O D. O - H ....F

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Which is correct order for bond dissociation energy in $ O_2 , O_2^+ , O_2 ^- AND O_2^{2-} $

$ O_2 \gt O_2 ^ + \gt O_2 ^ {2- } \gt O_2 ^ - $

$ O_2^+ \gt O_2 \gt O_2 ^ {- } \gt O_2 ^{2 -} $

$ O_2^- \gt O_2 ^{2-} \gt O_2 ^ {+ } \gt O_2 $

$ O_2^ - \gt O_2 ^{2-} + \gt O_2 \gt O_2 ^ + $

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Explanation

Bond order $O_2^+ = 2.5 $ $ O_2 = 2 $ $ O_2^- = 1.5 $ $ O_2 ^ {-2} = 1 $

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O, P, Q, R elements electronic configuration is given below $O = 1s^2$ $Q = 1s^2 , 2s^ 2 , 2p^5$ $P = 1s^2 , 2s^2 , 2p^2 $ $ R = 1s^2 , 2s^2 , 2p^6$ .Which atom has strong behaviour of electrovalent bond ?

A. O B. P C. Q D. R

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Explanation

Electrovalent bond (ionic bond) formation involves transfer of electrons from one atom to another, typically between a metal and a nonmetal. In the given configurations, element Q ($1s^2, 2s^2, 2p^5$) is one electron short of a stable noble gas configuration (like element R with $1s^2, 2s^2, 2p^6$). Hence, Q has a strong tendency to gain an electron, making it highly electrovalent.

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