Work Energy And Power MCQs for NEET — Physics Questions with Answers

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(ASSERTION & REASON) Assertion and Reason are given in following questions. Each question have four option. One of them is correct it. Assertion : Linear momentum is conserved in both, elastic and inelastic collisions. Reason : Total energy is conserved in all such collisins.

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Explanation

The assertion is that linear momentum is conserved in both elastic and inelastic collisions, which is true. The reason states that total energy is conserved in all such collisions. While energy conservation is true in elastic collisions, in inelastic collisions, only the total energy (kinetic energy + potential energy) is conserved, not just kinetic energy. Therefore, while both the assertion and reason are true, the reason does not correctly explain the assertion.

(ASSERTION & REASON) Assertion and Reason are given in following questions. Each question have four option. One of them is correct it. Assertion : Both, a stretched spring and a compressed spring have potential energy. Reason : Work is done against the restoring force in each case.

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Explanation

The assertion says that both a stretched spring and a compressed spring have potential energy, which is true. The reason is that work is done against the restoring force in each case, which is also true. When a spring is either stretched or compressed, work is done against the spring's restoring force, storing potential energy in the spring. Therefore, the reason correctly explains the assertion.

A force F = kx (where k is positive constant) is acting on a particle. Match column-I and column-II, regarding work done in displacing the particle. Column - I (a)From x = -4 to x = -2 (b)From x = -2 to x = -4 (c)From x = -2 to x = +2 Column - II (P) Positive (Q) zero (R) negative

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A body falls freely under the action of gravity from a height h above the ground. Column - I (a) P.E. = 2(K.E.) (b) P.E. = K.E. (c) P.E. = 2 (K.E.) (d) P.E.+ K.E. Column - II (P) constant at every point (Q) at height h/3 (R) at height 2h/3
(S) at height h/2

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Two vehicles moving on a horizontal road are stopped by same retarding force. Column - I (a) When they have same K.E. (b) When they have different masses but same velocity (c) When both have same momentum (d) When both have same mass but different velocities Column - II (P) faster body stop in larger distance (Q) larger body stops in larger distance. (R) heavier body stops in larger distance. (S) stopped in same distance.

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Which of the following is perpendicular to i^-j^-k^ ?

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Explanation

If vector A  is to B, B .A =0 Checking all optionsa) (i^ - j^ -k^). (i^ + j^ +k^) = 1-1-1 =-1   (Not perpendicular)b) (i^ - j^ -k^). (-i^ + j^ +k^) = -1-1-1 =-3   (Not perpendicular)c) (i^ - j^ -k^). (i^ + j^ -k^) = -1-1+1 =1   (Not perpendicular)So , no option matches. Answer is option D

Two constant forces F1=2i^-3j^+3k^ N and F2=i^+j^-2k^ N act on a body and displace it from the position r1=i^+2j^-2k^ m to the position r2=7i^+10j^+5k^ m. What is the work done?

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Explanation

(A)

 

Net force= F1+F2    Fnet= 2i^-3j^+3k^+i^+j^-2k^              = 3i^-2j^+k^Displacement r= r2-r1                                = 6i^+8j^+7k^Work done= Force. Displacement                   = Fnet.r                   = 3i^-2j^+k^.6i^+8j^+7k^                   = 18-16+7                   = 9 J

The two vectors A=2i^+j^+3k^ and B=7i^-5j^-3k^ are -

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Explanation

(B)

A.B=2×7+1×(-5)+3×(-3)=14-5-9=0perpendicular

Two vectors P=2i^+bj^+2k^ and Q=i^+j^+k^ will be perpendicular if -

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Explanation

(D)For P  Q  ,  Dot product  P.Q =0                      (2i^ +bj +2k^).  (i^ +j +k^) = 0                         2 +b +2 = 0                         b =-4

A vector perpendicular to 4i^-3j^ is -

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Explanation

(B)(4i^ - 3j^).7k ^ = 0So k ^ is the required vector

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