Work Energy And Power MCQs for NEET — Physics Questions with Answers

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A=i^+j^-k^ ; B=2i^+3j^+5k^ angle between A and B is

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Explanation

Angle between two vectors = cos-1A.BAB

=cos-12+3-53×38=cos-1(0)=90°

Given the vectors

                         A=2i^+3j^-k^                         B=3i^-2j^-2k^&                      C=pi^+pj^+2pk^

Find the angle between A-B & C

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Explanation

(C)

 

A-B= 2i^+3j^-k^-3i^-2j^-2k^          = -i^+5j^+k^Let A-B= D   let D= -i^+5j^+k^     D= -12+52+12    = 27To find the angle between D & CC= p2+p2+2p2   = P6D. C= DC cosθ-i^+5j^+k^. pi^+pj^+2pk^= 27×p6 cosθ-p+5p+2p= p27×6 cosθ6= 27×6 cosθcosθ= 627         = 29cosθ= 23    or    θ=cos-123

The vector having a magnitude of 10 and perpendicular to the vector 3i^-4j^ is 

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Explanation

3i+4j.8i+6j=0

A force F=3i^+cj^+2k^ acting on a particle causes a displacement d=-4i^+2j^+3k^. If the work done is 6J then the value of 'c' is

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Explanation

W=F.d6=F.d6=-12+2C+6C=6

A vector that is perpendicular to both the vectors a=i^-2j^+k^ and b=i^-j^+k^ is

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Explanation

(A)

 

 

i^+k^ = -i^+0j^+k^a.-i^+k^ = -1+0+1= 0b.-i^+k^ = -1+0+1= 0

If θ is the angle between vectors a and b, and |a×b|=a.b, then θ is equal to

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Explanation

Given, |a×b|=a.bab sinθ=ab cosθtan θ=1θ=45°

The vector b, which is collinear with the vector a=(2, 1, -1) and satisfies the condition a.b=3, is 

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Explanation

Going through the options;Only (A) satifies the condition a.b=3.

If 3i^+2j^+8k^ and 2i^+xj^+k^ are at right angle then x=

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Explanation

If two vectors are at right angle, then their dot product = 0

(3i^+2j^+8k^).(2i^+xj^+k^)=06+2x+8=0x=-7

If a, b, c are three non-zero vectors such that a+b+c=0 the value of a.b+b.c+c.a is

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Let α, β, γ be distinct real numbers. The points with position vectors αi^+βj^+γk^ , βi^+γj^+αk^ , γi^+αj^+βk^

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