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Mechanical Properties of Fluids MCQs for NEET — Physics Questions with Answers

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In a capillary tube, water rises by 1.2 mm. The height of water that will rise in another capillary tube having half the radius of the first, is

1.2 mm

2.4 mm

0.6 mm

0.4 mm

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Explanation

(b) $h \propto \frac{1}{r} ∴ r_{1} h_{1} = r_{2} h_{2} \Rightarrow h_{2} = \frac{r_{1} h_{1}}{r_{2}} = 2.4 mm$

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If capillary experiment is performed in vacuum, then for a liquid there capillary rise

It will rise

Will remain same

It will fall

Rise to the top

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Explanation

(b)

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If liquid level falls in a capillary then radius of capillary will

Increase

Decrease

Unchanged

None of these

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Explanation

(a) $h \propto \frac{1}{r} ∴ rh = constant$

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Water rises to a height h in a capillary at the surface of earth. On the surface of the moon the height of water column in the same capillary will be

$\frac{1}{6} h$

Zero

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Explanation

(a)

$h = \frac{2 Tcosθ}{rdg} ∴ h \propto \frac{1}{g} As g_{m} = \frac{g_{e}}{6} ∴ h_{m} = 6 h_{e}$

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Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50 dyne/cm respectively Ratio of heights of liquids in the two tubes $\frac{h_{1}}{h_{2}}$ is

$\frac{10}{9}$

$\frac{3}{10}$

$\frac{10}{3}$

$\frac{9}{10}$

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Explanation

(d) Ascent formula $h = \frac{2 Tcosθ}{rdg}$

$\Rightarrow \frac{h_{1}}{h_{2}} = \frac{T_{1}}{T_{2}} \times \frac{d_{2}}{d_{1}}$ (r, $θ$ and g are constants)

$= \frac{60}{50} \times \frac{0.6}{0.8} = \frac{9}{10}$

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Water rises in a vertical capillary tube upto a height of 2.0 cm . If the tube is inclined at an angle of $60 °$ with the vertical, then upto what length the water will rise in the tube ?

2.0 cm

4.0 cm

$\frac{4}{\sqrt{3}} cm$

$2 \sqrt{2} cm$

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Explanation

(b) $l = \frac{h}{cosθ} = \frac{2}{\cos 60 °} = 4.0 cm$

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The surface tension for pure water in a capillary tube experiment is

$\frac{ρg}{2 hr}$

$\frac{2}{ρghr}$

$\frac{rρg}{2 h}$

$\frac{hrρg}{2}$

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Explanation

(d) $T = \frac{rhdg}{2 cosθ}$ . For pure water $θ = 0 °$ so $T = \frac{rhdg}{2}$

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Kerosene oil rises up the wick in a lantern

Due to surface tension of the oil

The wick attracts the kerosene oil

Of the diffusion of the oil through the wick

None of the above

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Explanation

(a) Kerosene oil rises up the wick in a lantern due to the surface tension of the oil.

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Water rises against gravity in a capillary tube when its one end is dipped into water because

Pressure below the meniscus is less than atmospheric pressure

Pressure below the meniscus is more than atmospheric pressure

Capillary attracts water

Of viscosity

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Explanation

(a)

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A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is M. If the radius of the tube is doubled, mass of water that will rise in the capillary tube will now be

M/2

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Explanation

(b)

$Initial mass of liquid in the tube, M = {πR}^{2} H \times ρ When radius is doubled, As height of liquid α \frac{1}{radius} \Rightarrow Final height of liquid = \frac{H}{2} Final mass of liquid = π (2 R)^{2} \frac{H}{2} \times ρ = 2 M$

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