Kinetic Theory of Gases NEET प्रश्न हिंदी में — भौतिक विज्ञान (Physics) MCQ उत्तर सहित

$ PV = RT \Rightarrow = {PV \over RT } $ $ Mass of \mu litre nitrogen = \times M_o $

ऑक्सीजन का अणुभार = 32 (g) 5 g ऑक्सीजन में मोलों की संख्या = 5 /32 $ \therefore Equation of state is PV = RT$ $ PV = { 5 \over 32 } RT$

PV = RT $ \therefore Pv = \left( { M \over M_0 } \right) RT $ $ = \left( { M \over V } \right) {RT \over M_o } $ $ { \rho RT \over M_o } $ $ \left( {M \over V } = \rho \right) $ $ \Rightarrow { P \over \rho T } = { R \over M_o } = const $

$ \therefore PV \alpha T $ $ ( R --> constant ) $ $ PV = RT = \left( { M \over M_o } \right) RT $ $ \therefore { M \over PV } = { M_o \over RT} $ $ \therefore { density \over P } = { M_o \over RT } $ $ \therefore \left( { density \ over P } \right) _ { at 0 c } = { M \over R (273 ) } = x$ .......(i) $ \therefore \left( { density \ over P } \right) _ { at 100 c } = { M \over R (373 ) } $ .......(ii) $ \therefore \left( { density \ over P } \right) _ { at 100 c } = \left ( { 273 \over 373} \right) x$

PV = RT $ = \left ( {M \over M_o} \right) RT \Rightarrow V = { MRT \over M_o P } $

PV =RT $ { P_1 V_1 \over P_2 V_2 } = {1 \over 2 } $ ( T नियत )

$ V \alpha T \Rightarrow { V_1 \over V_2 } = {T_1 \over T_2 } $

$ { P_1 V_1 \over T_1 } = { P_2 V_2 \over T_2 } \Rightarrow T_2 = \left( { P_2 V_2 \over P_1 V_1 } \right) T_1 $

$ Pressure P = { F \over A } = { 1 \over A } { \triangle P \over \triangle t } $ $ ( \triangle P = change in momentum) $

$$ P = {2 \over 3 } ( Energy per unit volume ) $$ $$ = { 2 \over 3 } { E \over V } = { 2 \over 3 } E $$